Given that log\(_3\) 27 = 2x + 1, find the value of x.
Recall that: log\(_3\) 27 → log\(_3\)3\(^3\)
3log\(_3\)3 → 3 * 1
= 3
Then log\(_3\) 27 = 2x + 1
→ 3 = 2x + 1
3 - 1 = 2x
2 = 2x
1 = x
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