Given that sin (5x-28)° = cos (3x-50)", 0°≤ x ≤ 90°, find the value of x.

Lexino

1 year ago

sin(5x-28) = cos(3x-50)
But sin(5x-28) = cos ( 90 - (5x-28))
cos (3x-50) = cos ( 90 -5x+28)
(3x-50) = (90-5x+28)
3x-50 = 90-5x+28
3x+5x = 90+28+50
8x = 168
x = 21⁰

goodlive715

1 year ago

The answer is wrong dear My School the answer is 21 not 32 pls recheck

iamutibe

1 year ago

The question is wrongly composed

tobimbhs

1 month ago

THERE ARE TWO B