Make t the subject of k = \(m \sqrt \frac{t-p}{r}\)
a
\(\frac{k^2r + p}{m^2}\)
b
\(\frac{k^2r + pm^2}{m^2}\)
c
\(\frac{k^2r - p}{m^2}\)
d
\(\frac{k^2r + p^2}{m^2}\)
Explanation
Correct Option
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mathew192
2 years ago
A as answer; B as the answer;
K=m√t-p/r. K=m√t-p/r
k/m=√t-p/r. K/m=√t-p/r
k²/m²=t-p/r. k²/m²=t-p/r
m²(t-p)=k²r. m²t-m²p=k²r
(t-p)=k²r/m². m²t=k²r+m²p
t=(k²r +p)/m². t=(k²r+m²p)/m².
