Given that S = \(3t^{2}\) + 5t - 10 is displacement of a particle in metres, calculate it initial velocity.

Doner1

3 years ago

S= 3t² + 5t - 10
The initial velocity would be the derivative of the equation.
V= ds/dt = 6t + 5
at initial velocity
t = 0
Hence, v= 6(0) + 5
v= 5m/s

Brovic02

1 year ago

Their is no explanation

Johwey

1 year ago

I THOUGHT "V" IS FINAL VELOCITY NOT INITIAL VELOCITY???