Integrate (2x+1)\(^3\)
Recall chain rule:
u = 2x +1; du = 2dx → dx = \(\frac{du}{2}\) u\(^3\) = ∫ u\(^3\) \(\frac{du}{2}\) → \(\frac{1}{2}\) ∫ u\(^3\)
= \(\frac{1*u^4}{2*4}\)
= \(\frac{u^4}{8}\) → \(\frac{{2x+1}^4}{8}\) + C
There is an explanation video available below.
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