(a) A man shared his property among his children as follows:
|
Child's name |
Ann | Afia | Kojo | Nuno |
Akom |
|
Percentage share |
5 | 15 | 10 | 45 |
25 |
Represent the information on a pie chart
(b) A box contains 5 red, 3 green and 4 blue identical beads. Calculate the probability th a girl takes away two red beads, one after the other, from the box.
(a)
|
Child's Name |
Percentage Share (%) |
Angle(°) |
|
Ann |
5 |
5/100 * 360" = 18 |
|
Afia |
15 |
15/100 x 360° = 54 |
|
Kojo |
10 |
10/100 x 360° = 36 |
|
Nuno |
45 |
45/100 x 360° = 162 |
|
Akosua |
25 |
25/100 x 360° = 90 |
|
Total |
100 |
360 |
(b) P(1st red) = 5/12
P(2nd red) = 4/11
Probability (two red beads) = 5/12 * 4/11
= 5/33 (Accept 0.1515)
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