In the diagram, \(\overline{AD}\) is a diameter of a circle with Centre O. If ABD is a triangle in a semi-circle ∠OAB=34",

find: (a) ∠OBD (b) ∠OCB

 

Masterman01

4 years ago

Pls check this solution again ,

Jayjay54

1 year ago

I have reported on this question before now. The answer supplied assumes that BC is a tangent to the circle; but the question should have stated so.

Christy8

5 months ago

please when answering a geometric question, state the reason for the step .... examples "angle at the centre is twice angle at the circumference "

Tim234D

1 year ago

Greetings, The Myschool Team.
From the explanation given, part (a) is asking for the value of

Masterman01

4 years ago

Pls check the solution again

SECONDLY,I think it is angle ABD that is 90 and not this follows the theorem that says that angle in a semicircle is a right angle