2021 WAEC Mathematics Theory In the diagram, \(\overline{AD}\) is a diameter of a circle with Centre O. If ABD...

In the diagram, \(\overline{AD}\) is a diameter of a circle with Centre O. If ABD is a triangle in a semi-circle ∠OAB=34",

find: (a) ∠OBD (b) ∠OCB

∠OAB = ∠OBA=34° (base <s of isosceles triangle)

∠ABD = 90( angle in a semi circle)

∠OBD = ∠ABD - ∠0BA = 90 - 34 = 56

From triangle OBC

∠BOC + ∠OBC + ∠OCB = 180° (sum of angles in a triangle)

∠BOD = ∠2OAB = 68°

= 68° + 90° + ∠0CB = 180

∠OCB = 180 - 158 = 22

Previous Next

{{ settings.no_comment_msg ? settings.no_comment_msg : 'There are no comments' }}