2021 WAEC Mathematics Theory The points X, Y and Z are located such that Y is 15 km south...

The points X, Y and Z are located such that Y is 15 km south of X, Z is 20 km from X on a bearing of 270".

Calculate, correct: (a) two significant figures, |YZ|

(b) The nearest degree, the bearing of Y from Z

|YZ|\(^2\) = 15\(^2\) + 20\(^2\)

= 225 + 400 = 625

YZ = √625

YZ = 25

(b) tan θ = \(\frac{15}{20}\)

tan θ = 0.75

θ = tan -1 (0.75)

= 36.87°

Bearing of Y from Z = (90 + 36.87)° = 126.87°

= 127°

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