A box contains 40 identical balls of which 10 are red and 12 are blue. if a ball is selected at random from the box what is the probability that it is neither red nor blue?
a
\(\frac{9}{20}\)
b
\(\frac{3}{10}\)
c
\(\frac{1}{4}\)
d
\(\frac{11}{20}\)
Explanation
Correct Option
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