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Given that sin x = 3/5, 0 ≤ x ≤ 90, evaluate (tanx + 2cosx)  

Mathematics
WAEC 2021

Given that sin x = 3/5, 0 ≤ x ≤ 90, evaluate (tanx + 2cosx)

 

  • A. 2\(\frac{11}{20}\)
  • A. \(\frac{11}{20}\)
  • B. 2\(\frac{7}{20}\)
  • D. \(\frac{1}{20}\)
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Correct Answer: Option B
Explanation

Sin x = \(\frac{opp}{hyp}\)

sinx = \(\frac{3}{5}\)

using Pythagoras' theorem

 hyp\(^2\) = opp\(^2\) + adj\(^2\)

adj\(^2\) = 5\(^2\) - 3\(^2\) = 25 - 9

adj\(^2\) = 16 

adj =  16 

adj = 4.

tanx = \(\frac{opp}{adj}\)

= \(\frac{3}{4}\)

cosx = \(\frac{adj}{hyp}\)

= \(\frac{4}{5}\)

(tanx + 2cosx) = \(\frac{3}{4}\) + 2(\(\frac{4}{5}\))

= \(\frac{15 + 32}{20}\)

= \(\frac{47}{20}\) or 

2 \(\frac{7}{20}\)


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Join your school's WhatsApp group
NECO June/July 2024 - Get offline past questions & answers - Download objective & theory, all in one app 48789
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
NECO June/July 2024 - Get offline past questions & answers - Download objective & theory, all in one app 48789
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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