A cyclist moved at a speed of Xkm/h for 2 hours. He then increased his speed by 2 km/h for the next 3 hours.

If the total distance covered is 36 km, calculate his initials speed.

rosemary1156

4 years ago

Distance = speed × time
First/Initial speed = x
Second/Latter speed = x + 2
First/Initial time = 2 hours
Latter time = 3 hours
Total distance = initial distance + latter distance
36 = Initial speed X Initial time + latter speed X latter time
36 = x X 2 + x+2 X 3
36 = 2x + 3x + 6
36 - 6 = 5x
30 = 5x
X = 6km

DannySamuel

1 year ago

no correct answer

Jayprince55

9 months ago

pls what is the answer

mitchell.e

1 year ago

answer not there, you feel me my ni**a

hamuy

2 years ago

15km/h

Divineelite74

2 years ago

speed 1 - xkm/h
speed 2 - (2 * x)km/h = 2xkm/h
time 1 - 2 hours
time 2 = 3 hours
Distance = speed *time
(speed 1 * time 1) + (speed 2 * time 2)
(2x *2)+(3*2x) = 2x+6x = 8x
36=8x
x=36/8
x=4.5

Sundsl

4 years ago

Total distance covered= average speed x Total time taken
initial speed = Xkm/hr
final speed = 2km/hr
Total time taken = 2+3= 5sec.
Total distance covered = 36km/hr
average speed = (X+2)/2
plugin the parameters into the formula above.
36 = (x+2)/2 x5
36 = (5x+10)/2
cross multiply
5x+10 = 72
5x = 72-10
5x = 62
divide both sides by 5
5x/5= 62/5
x = 12.4 = 12km, to the nearest km.