Which of the following is not an exterior angle of a regular polygon?

loveella

4 years ago

all the options except 66 are factors of 360
for 5 sides =360°/5
=72°
for 15 sides=360°/15
=24°
for 24 sides=360°/24
=15°

Nadja

3 years ago

Exterior angle of a polygon =360/theta
the above formula, should be perfectly divisible by 360.
Of all the options given, 66° cannot divide 360 without a remainder, hence, (A) is the right answer

Christiana090327

1 year ago

solution
Formula for exterior angle of a regular polygon = 360°/n , where n = number of side of a polygon.

Using 66° in option A to get n(which is the number of sides)
360°/n = 66°
cross multiply, you get,
360 = 66n
Divide both sides by 66 to make get n (number of sides)
So, n = 5.454545....

Since number of sides of a regular polygon cannot be in decimal number, therefore 66° is not an exterior angle of a regular. Try fixing the other options in the equation in place of 66° for checking and you will get a whole number.