If \(\frac{2}{x-3}\) - \(\frac{3}{x-2}\) = \(\frac{p}{(x-3)(x -2)}\), find p.
\(\frac{2}{x-3}\) - \(\frac{3}{x-2}\)
= \(\frac{2(x -2) -3(x - 3)}{(x-3)(x -2)}\)
= \(\frac{2x -4 -3x + 9}{(x-3)(x -2)}\)
= \(\frac{5 - x}{(x-3)(x -2)}\)
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