If log\(_{10}\) 2 = m and log\(_{10}\) 3 = n, find log\(_{10}\) 24 in terms of m and n.
log\(_{10}\) 24 = log\(_{10}\) 8 \(\times\) log\(_{10}\) 3
where log\(_{10}\) 8 = 3 log\(_{10}\) 2 = 3 \(\times\) m
and log\(_{10}\) 3 = n
: log\(_{10}\) 24 = 3m + n
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