Solve: 2\(^{√2x + 1}\) = 32
2\(^{√2x + 1}\) = 32
2\(^{√2x + 1}\) = 2\(^5\)
√2x + 1 = 5
square both sides
2x + 1 = 5\(^2\)
2x + 1 = 25
2x = 25 - 1
2x = 24
x = \(\frac{24}{2}\)
x = 12
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