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Solve: 2\(^{\sqrt{2x + 1}}\) = 32

Mathematics
WAEC 2021

Solve: 2\(^{\sqrt{2x + 1}}\) = 32

  • A. 13
  • B. 24
  • C. 12
  • D. 11
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Correct Answer: Option C
Explanation

2\(^{\sqrt{2x + 1}}\) = 32

2\(^{\sqrt{2x + 1}}\) = 2\(^5\)

\(\sqrt{2x + 1}\) = 5

square both sides

2x + 1 = 5\(^2\)

2x + 1 = 25

2x = 25 - 1

2x = 24

x = \(\frac{24}{2}\)

x = 12


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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 127076
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