Correct Answer: Option C

Explanation

Numbers: 1 (odd), 2 (even), 3 (odd), 4 (even)

Total ways to remove 2 numbers out of 4 = C(4,2) = 6 possible pairs:

- (1,2) → odd + even = odd
- (1,3) → odd + odd = even
- (1,4) → odd + even = odd
- (2,3) → even + odd = odd
- (2,4) → even + even = even
- (3,4) → odd + even = odd

Favourable outcomes (even sum): (1,3) and (2,4) → 2 ways

Probability = \(\frac{2}{6}\) = \(\frac{1}{3}\)

There is an explanation video available below.

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