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Make m the subject of the relation k = \(\sqrt{\frac{m - y}{m + 1}}\)

Mathematics
WAEC 2020

Make m the subject of the relation k = \(\sqrt{\frac{m - y}{m + 1}}\)

  • A. m = \(\frac{y + k^2}{k^2 + 1}\)
  • B. m = \(\frac{y + k^2}{1 - k^2}\)
  • C. m = \(\frac{y - k^2}{k^2 + 1}\)
  • D. m = \(\frac{y - k^2}{1 - k^2}\)
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Correct Answer: Option B
Explanation

k = \(\sqrt{\frac{m - y}{m + 1}}\)

k\(^2\) = \(\frac{m  - y}{m + 1}\)

k\(^2\)m + k\(^2\) = m - y 

k\(^2\) + y = m - k\(^2\)m

\(\frac{k^2 + y}{1 - k^2}\) = m\(\frac{(1 - k^2)}{1 - k^2}\)

m = \(\frac{y + k^2}{1 - k^2}\)


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WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709