Make m the subject of the relation k = \(\sqrt{\frac{m - y}{m + 1}}\)
a
m = \(\frac{y + k^2}{k^2 + 1}\)
b
m = \(\frac{y + k^2}{1 - k^2}\)
c
m = \(\frac{y - k^2}{k^2 + 1}\)
d
m = \(\frac{y - k^2}{1 - k^2}\)
Explanation
Correct Option
bVideo Explanation
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