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Given that \(\frac{\sqrt{3} + \sqrt{5}}{\sqrt{5}}\)  = x + y\(\sqrt{15}\), find the value of (x +...

Mathematics
WAEC 2020

Given that \(\frac{\sqrt{3} + \sqrt{5}}{\sqrt{5}}\) 

= x + y\(\sqrt{15}\), find the value of (x + y) 

  • A. 1\(\frac{3}{5}\)
  • B. 1\(\frac{2}{5}\)
  • C. 1\(\frac{1}{5}\)
  • D. \(\frac{1}{5}\)
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Correct Answer: Option C
Explanation

\(\frac{\sqrt{3} + \sqrt{5}}{\sqrt{5}}\)  = x + y\(\sqrt{15}\)

cross multiply to have: \(\sqrt{3}\) + \(\sqrt{5}\) =  x\(\sqrt{5}\) + 5y\(\sqrt{3}\)

Collect like roots :   x\(\sqrt{5}\) =  \(\sqrt{5}\) → x = 1

                                5y\(\sqrt{3}\) =  \(\sqrt{3}\) → y = \(\frac{1}{5}\)

∴ ( x + y ) = 1 + \(\frac{1}{5}\)

= 1\(\frac{1}{5}\)

                           


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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
NECO June/July 2024 - Get offline past questions & answers - Download objective & theory, all in one app 48789
Join your school's WhatsApp group
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
Join your school's WhatsApp group
NECO June/July 2024 - Get offline past questions & answers - Download objective & theory, all in one app 48789
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709