If 101\(_{\text{two}}\) + 12\(_y\) = 23\(_{\text{five}}\). Find the value of y
012 + 01 = 01
101\(_2\) + 12\(_y\) = 23\(_5\)
1 x 2\(^o\) + 0 x 2\(^o\) + 1 x2\(^2\) + 1 x y\(^o\) + 2 x y\(^1\) = 3 x 5\(^o\) + 3 x 5\(^1\)
1 + 4 + 1 + 2y = 3 + 15
6 + 2y = 18
2y = 18 - 6
\(\frac{2y}{2} = \frac{12}{2}\)
y = 6
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