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2019 WAEC Mathematics Theory  A woman bought 130 kg of tomatoes for 52,000.00. She sold half of the tomatoes...

Mathematics
WAEC 2019

 A woman bought 130 kg of tomatoes for 52,000.00. She sold half of the tomatoes at a profit of 30%. The rest of the tomatoes began to go bad, she then reduced the selling price per kg by 12%. Calculate:

(a) the new selling price per kg;

(ii) the percentage profit on the entire sales if she threw away 5 kg of bad tomatoes.

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Explanation

(a) Weight of full tomatoes = 130kg

Weight of half tomatoes = \(\frac{130}{2}\) = 65kg

Cost price of half tomatoes = \(\frac{N52,000}{2}\) 

= N26,000

 

Profit = \(\frac{S.P - C.P}{C.P}\) x 100

30 = \(\frac{(S.P - 26,000)}{25,000}\) x 100

S.P = N7800 + N26,000

S.P = N7,800 + N26,000

S.P of half tomatoes = N33,800

Selling price per kg = \(\frac{33,800}{65}\) 

= N520 per  kg

Reduction in selling price = 12% 

= \(\frac{12}{100}\) x 520 = N62.40k per kg

New selling price per kg 

= N520 - N62.40k

= N457.60k

 

(b) 5kg is thrown away remaining 60kg 

The selling price of entire 60kg

= 60 x N457.60k = N27,456

The entire selling price 

N33,800 + N27,456

= N61,256

% profit = \(\frac{(61.256 - 50,000)}{52,000}\) x 100

= 17.8%


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WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts