Three red balls, five green balls, and a number of blue balls are put together in a sack. One ball is picked at random from the sack. If the probability of picking a red ball is \(\frac{1}{6}\) find;

(a) The number of blue balls in the sack 

(b) the probability of picking a green ball

LuCAz001

4 years ago

This answer is wrong i think... After x{blue ball} has been gotten which is 10..
The number of total outcome is 3+5+10 which equals 18

So if a ball is picked at random, that is 18-1 which is 17

So the p of green ball is 5/17

LuCAz001

4 years ago

This answer is wrong i think... After x{blue ball} has been gotten which is 10..
The number of total outcome is 3+5+10 which equals 18

So if a ball is picked at random, that is 18-1 which is 17

So the p of green ball is 5/17