Find the equation of a straight line passing through the point (1, -5) and having gradient of \(\frac{3}{4}\)
\(\frac{3}{4} = \frac{y + 5}{x - 1}\)
3(x - 1) = 4(y + 5)
3x - 3 = 4y + 20
3x - 4y - 23 = 0
Please don't post or ask to join a "Group" or "Whatsapp Group" as a comment. It will be deleted. To join or start a group, please click here
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}