A box contains 2 white and 3 blue identical balls. If two balls are picked at random from the box, one after the other with replacement, what is the probability that they are of different colours?
a
\(\frac{2}{3}\)
b
\(\frac{3}{5}\)
c
\(\frac{7}{20}\)
d
\(\frac{12}{25}\)
Explanation
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Discussions (6)
Nedaman
3 years ago
Please kindly correct the number of white and blue balls. They cannot have the same number 3 given the options below.
If the numbers are the same then the p(white)= 1/2 and p(blue)= 1/2.
Therefore the p(different colours) = p(WB)+p(BW)= 1/2×1/2 + 1/2×1/2
= 1/2
olaolu357
1 year ago
sorry your explation states the answer is 12/25 but the answer selected is 7/20 which is wrong.please adjust
