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Make b the subject of the relation lb = \(\frac{1}{2}\) (a + b)h

Mathematics
WAEC 2019

Make b the subject of the relation lb = \(\frac{1}{2}\) (a + b)h

  • A. \(\frac{ah}{2l - h}\)
  • B. \(\frac{2l - h}{al}\)
  • C. \(\frac{al}{2l - h}\)
  • D. \(\frac{al}{2 - h}\)
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Correct Answer: Option A
Explanation

lb = \(\frac{1}{2} (a + b)h

2lb = ah + bh

2lb - bh = ah

\(\frac{b(2l - h)}{2l - h} = \frac{ah}{2l - h}\)

b = \(\frac{ah}{2l - h}\)

 

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts