In XYZ, |YZ| = 32cm, < YXZ 53\(^o\) and XZY = 90\(^o\). Find, correct to the nearest centimetre, |XZ|
Tan 52\(^o\) = \(\frac{32}{\text{|XZ|}}\)
|XZ| = \(\frac{32}{Tan 52^o}\)
= 25cm
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