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Simplify: \(\log_{10}\) 6 - 3 log\(_{10}\)  3 + \(\frac{2}{3} \log_{10} 27\)

Mathematics
WAEC 2019

Simplify: \(\log_{10}\) 6 - 3 log\(_{10}\)  3 + \(\frac{2}{3} \log_{10} 27\)

  • A. 3 \(\log_{10}^2\)
  • B. \(\log_{10}^2\)
  • C. \(\log_{10}^3\)
  • D. 2 \(\log_{10}^3\)
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Correct Answer: Option B
Explanation

log\(_{10}\) 6 - log\(_{10}\)3\(^3\) + log\(_{10}\) (\(\sqrt[3]{27}\))\(^2\)

= log \(_{10}\) 6 - log \(_{10}\) 27 + log\(_{10}\) 9

= log\(_{10}\) \(\frac{6  \times 9}{27}\)

= log\(_{10}\)2

 


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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free