Solve \(4x^{2}\) - 16x + 15 = 0.
a
x = 1\(\frac{1}{2}\) or x = -2\(\frac{1}{2}\)
b
x = 1\(\frac{1}{2}\) or x = 2\(\frac{1}{2}\)
c
x = 1\(\frac{1}{2}\) or x = -1\(\frac{1}{2}\)
d
x = -1\(\frac{1}{2}\) or x -2\(\frac{1}{2}\)
Explanation
Correct Option
bVideo Explanation
No video available
Post your Contribution
Share:
