H varies directly as p and inversely as the square of y. If H = 1, p = 8 and y = 2, find H in terms of p and y.
a
H = \(\frac{p}{4y^2}\)
b
H = \(\frac{2p}{y^2}\)
c
H = \(\frac{p}{2y^2}\)
d
H = \(\frac{p}{y^2}\)
Explanation
Correct Option
cVideo Explanation
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