A cylindrical tank has a capacity of 3080m\(^3\). What is the depth of the tank if the diameter of its base is 14m?
V = 2080cm\(^3\), h = ?
r = 7cm
V = V\(\pi r^2h\)
h = \(\frac{V}{\pi r^2} = \frac{3080}{\frac{22}{7} \times 49}\)
\(\frac{3080}{54}\) = 20cm
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