If x is positive real number, find the range of values for which \(\frac{1}{3x}\) + \(\frac{1}{2}\) > \(\frac{1}{4x}\)
x > -\(\frac{1}{6}\)
x > 0
0 < x < 6
0 < x <\(\frac{1}{6}\)
Explanation
Video Explanation
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The question is wrong! The explanation video has a different question. Do not bother trying to figure out what is wrong with your solution
I don't really know if I can trust the legitimacy of these platform. The questions and answers many times contradict. This question and workings are very inaccurate. I think it is as a result of inadequate editing. It's a good resource but I still don't get the thrill I'm looking for on this platform.
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According to the option and solution provided, then it should be seen clear that their is an error while composing the question
This Steps might help:
1/3x + 1/2 > 1/4x
multiply through by 12x as their common factor
12x * 1/3x + 12x * 1/2 > 12x * 1/4x
You'll have: 4 + 6x > 3
Collect like terms: 6x > -1
Divide both sides by 6: x > -1/6
Watch the Video and leave that Solved Explanation for now 
