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In this fiqure, PQ = PR = PS and SRT = 68\(^o\). Find QPS 

Mathematics
JAMB 2020

In this fiqure, PQ = PR = PS and SRT = 68\(^o\). Find QPS 

  • A. 136\(^o\)
  • B. 124\(^o\)
  • C. 112\(^o\)
  • D. 68\(^o\)
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Correct Answer: Option A
Explanation

Since PQRS is quadrilateral

2y + 2x + QPS = 360\(^o\)

i.e. (y + x) + QPS = 360\(^o\) 

QPS = 360\(^o\) - 2 (y + x)

But x + y + 68\(^o\) = 180\(^o\)

There; x + y = 180\(^o\) - 68\(^o\) = 112\(^o\)

QPS = 360 - 2(112\(^o\))

= 360\(^o\) - 224 = 136\(^o\)

There is an explanation video available below.


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Explanation Video

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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709