If log\(_{10}\)2 = 0.3010 and log\(_{10}\)3 = 0.4771, eventually without using the logarithm tables, log\(_{10}\)4.5
log\(_{10}\)2 = 0.3010 and log\(_{10}\)3 = 04771
log\(_{10} 4.5 = log_{10}\) (\(\frac{3 \times 3}{2}\))
log\(_{10}\) 3 + log\(_{10}\) 3 - log\(_{10}\)2 = 0.4471 + 0.771 - 0.3010
= 0.6532
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