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2019 WAEC Mathematics Theory (a) Given that 110\(_x\) - 40\(_{five}\). find the value of x (b) Simplify \(\frac{15}{\sqrt{75}} +...

Mathematics
WAEC 2019

(a) Given that 110\(_x\) - 40\(_{five}\). find the value of x

(b) Simplify \(\frac{15}{\sqrt{75}} + \(\sqrt{108}\) + \(\sqrt{432}\), leaving the answer in the form a\(\sqrt{b}\), where a and b are positive integers.
 

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Explanation

(a)110\(_x\) - 40\(_{5}\)

1 x  \(x^2}\) + 1 x \(x^1\) + 0 x \(x^o\)

x = 4 x 5\(^1\) + 0 x 5\(^o\)

x\(^2\) + x = 4 x 5 + 0

x\(^2\) + x - 20 = 0

(x - 4)(x + 5) = 0

x - 4 = 0 or x + 5 = 0

x = 4 or x = -5

x = 4

 

(b) Simplify \(\frac{15}{\sqrt{75}}\)  + \(\sqrt{108}\) + \(\sqrt{432}\)

 = \(\frac{15}{\sqrt{25 \times 3}}\)  + \(\sqrt{36 \times 3}\)

= \(\frac{15}{5 \sqrt{3}\) + 6\(\sqrt{3}\) + 12\(\sqrt{3}\)

= \(\frac{15 \sqrt{3}}{15 \times \sqrt{3} \times \sqrt{3}}\) + 18\(\sqrt{3}\)

= \(\frac{15\sqrt{3}}{15}\) + 18\(\sqrt{3}\)

\(\sqrt{3}\) + 18\(\sqrt{3}\) = 19\(\sqrt{3}\)

 


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Project Topics and Materials, Post-UTME past questions - Download now or upload yours to get paid
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
NECO June/July 2024 - Get offline past questions & answers - Download objective & theory, all in one app 48789
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Project Topics and Materials, Post-UTME past questions - Download now or upload yours to get paid
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts