Evaluate \(\frac{(2.813 \times 10^{-3} \times 1.063)}{(5.637 \times 10^{-2})}\) reducing each number to two significant figures and leaving your answer in two significant figures.

a

0.056

b

0.055

c

0.054

d

0.54

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Explanation

Correct Option
b

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Discussions (58)

Prisbeeadins
3 years ago

Evaluate
2•813×10^-3×1•063÷5•637×10^-2

solve
2•813×10^-3
=0•02813

approximate 1•063=(1•1)

then
0•02813×1•1
=0•030943

now going for the denominator
5•637×10^-2
=0•05637

next approximation:
approximating 0•030943=(0•031)
approximating 0•05637=(0•056)

then divide 0•031 by 0•056
giving your answer to 2 significant figures
=0•055.

Chibuikegerald60
10 years ago

I also got 0.0530

Tomskike
10 years ago

Sowie I Got 0.0530

Uchechukwuben
2 years ago

Pls break it down for me

ibrajat16
10 years ago

D ANSA IS NT AVAILABLE IN OPTION

Champion26
3 years ago

We are meant to approximate first before evaluating, and that's the only way to end up with the right answer, remember no calculator in Jamb

gluguyj
11 years ago

i got 0.0530 ooo

Ifunanya123456
2 years ago

The answer is correct guys
Read the question very well
it states to to reduce each number to two significant figures before solving

Asanwa722
1 year ago

the answer is 0.055

amaraxy
6 years ago

The answer is correct ooo guys

Itzaliana
1 year ago

The answer is supposed to be 0.053

Prettychukwuneke
2 years ago

To Evaluate (2.813× 10−3× 1.063)(5.637× 10−2) reducing each number to two significant figures and leaving your answer in two significant figures.

To evaluate the expression, let's first perform the multiplication:

(2.813 × 10^(-3) × 1.063) × (5.637 × 10^(-2))

= (2.99 × 10^(-3)) × (5.6 × 10^(-2))

Now, multiply the numbers:

2.99 × 5.6 ≈ 16.7

And add the exponents:

10^(-3) × 10^(-2) = 10^(-5)

So, the result is approximately 16.7 × 10^(-5), which, reduced to two significant figures, is approximately 17 × 10^(-5).

leo59
10 years ago

The answer is nt in the option...I got 0.053

EbiCosmus
2 years ago

The reason for their answer is their approximation of "1.063 to 1.1". If they didn't, then their answer would also be "0.053" like the rest of us.

But truth be told, I don't see any need for the approximation.

peculiar abacus
11 years ago

Same here I got 0.053

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