A shop had two reduction sales during which prices of all items were reduced by 40% in the first sales and 30% in the second.
(a) let the original price of the shirt be x, then we have two percentages reduction leaving 60% and 70%. This implies that \(\frac{60}{100} \times \frac{70}{100} \times x\) = 35.
Solving for x yields x = GH₵ 83.33.
(b) (i), the first reduction = (\(\frac{40}{100}\)) x 180 = 72.00 and the second reduction = (\(\frac{30}{100}\) ) x 108 = 32.40.
Then total reduction = (72.00 + 32. 40) = GH₵ 104.40.
(b) (ii), the percentage reduction in the price of the article = (\(\frac{104.40}{180} \times 100\)) = 58%
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