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Evaluate \(\frac{2\sin 30 + 5\tan 60}{\sin 60}\), leaving your answer in surd form.

Mathematics
JAMB 2019

Evaluate \(\frac{2\sin 30 + 5\tan 60}{\sin 60}\), leaving your answer in surd form.

  • A. \(\frac{2\sqrt{3}}{3} + 10\)
  • B. \(\frac{3\sqrt{2} - 1}{5}\)
  • C. \(\frac{3\sqrt{2} + 1}{5}\)
  • D. \(\frac{2\sqrt{3}}{3} - 10\)
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Correct Answer: Option A
Explanation

\(\frac{2\sin 30 + 5\tan 60}{\sin 60}\)

\(\sin 30 = \frac{1}{2}; \tan 60 = \sqrt{3}; \sin 60 = \frac{\sqrt{3}}{2}\)

\(\therefore \frac{2\sin 30 + 5\tan 60}{\sin 60} = \frac{2(\frac{1}{2}) + 5(\sqrt{3})}{\frac{\sqrt{3}}{2}}\)\)

= \(\frac{1 + 5\sqrt{3}}{\frac{\sqrt{3}}{2}}\)

= \(\frac{2(1 + 5\sqrt{3})}{\sqrt{3}}\)

= \(\frac{2 + 10\sqrt{3}}{\sqrt{3}}\)

Rationalizing, we get

= \(\frac{2\sqrt{3} + 30}{3}\)

= \(\frac{2}{3} \sqrt{3} + 10\)

There is an explanation video available below.


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Explanation Video

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WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC offline past questions - with all answers and explanations in one app - Download for free