Find the equation of a line perpendicular to the line 4y = 7x + 3 which passes through (-3, 1)

Michealubegirl

5 years ago

4y=7x+3
m=7/4
using formula for perpendicular line=m1m2=-1
7/4*m2=-1
m2=-4/7
(-3,1)
-4/7=y-1/x+3
7(y-1)=-4(x+3)
7y-7=-4x-12
7y=-4x-12+7
7y=-4x-5
7y+4x+5=0 (A) correct ans