A binary operation Δ is defined by a Δ b = a + 3b + 2. Find (3 Δ 2) Δ 5
a Δ b = a + 3b + 2
(3 Δ 2) Δ 5 = (3 + 3(2) + 2) Δ 5
= 11 Δ 5
= 11 + 3(5) + 2
= 28
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