If the volume of a frustrum is given as \(V = \frac{\pi h}{3} (R^2 + Rr + r^2)\), find \(\frac{\mathrm d V}{\mathrm d R}\).
a
\(\frac{\pi h}{3} (2R + r)\)
b
\(2R + r + \frac{\pi h}{3}\)
c
\(\frac{\pi h}{3} (2R^2 + r + 2r)\)
d
\(\frac{2R^2}{3} \pi h\)
Explanation
Correct Option
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DivineChinemerem
1 year ago
The square on the r when differentiated would be 2r. Therefore, the answer would be πh/3 (2R + 2r)
