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Solve for x in \(\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}\)

Mathematics
JAMB 2019

Solve for x in \(\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}\)

  • A. \(x \leq 1\frac{1}{2}\)
  • B. \(x \leq \frac{21}{2}\)
  • C. \(x \geq \frac{21}{2}\)
  • D. \(x \geq 1\frac{1}{2}\)
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Correct Answer: Option B
Explanation

\(\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}\)

2(4x - 6) \(\leq\) 3(3 + 2x)

8x - 12 \(\leq\) 9 + 6x

8x - 6x \(\leq\) 9 + 12

2x \(\leq\) 21

\(x \leq \frac{21}{2}\)

There is an explanation video available below.


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Explanation Video

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