\(\frac{d}{dx} [\log (4x^3 - 2x)]\) is equal to
a
\(\frac{12x - 2}{4x^2}\)
b
\(\frac{43x^2 - 2x}{7x}\)
c
\(\frac{4x^2 - 2}{7x + 6}\)
d
\(\frac{12x^2 - 2}{4x^3 - 2x}\)
Explanation
Correct Option
dVideo Explanation
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\(\frac{d}{dx} [\log (4x^3 - 2x)]\) is equal to
\(\frac{12x - 2}{4x^2}\)
\(\frac{43x^2 - 2x}{7x}\)
\(\frac{4x^2 - 2}{7x + 6}\)
\(\frac{12x^2 - 2}{4x^3 - 2x}\)
