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If \(4\sin^2 x - 3 = 0\), find the value of x, when 0° \(\leq\)...

Mathematics
JAMB 2019

If \(4\sin^2 x - 3 = 0\), find the value of x, when 0° \(\leq\) x \(\leq\) 90°

  • A. 90°
  • B. 45°
  • C. 60°
  • D. 30°
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Correct Answer: Option C
Explanation

\(4\sin^2 x - 3 = 0\)

\(4 \sin^2 x = 3 \implies \sin^2 x = \frac{3}{4}\)

\(\sin x = \frac{\sqrt{3}}{2}\)

\(\therefore x = \sin^{-1} (\frac{\sqrt{3}}{2})\)

x = 60°

There is an explanation video available below.


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Explanation Video

WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts