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In triangle PQR, q = 8 cm, r = 6 cm and cos P =...

Mathematics
JAMB 2013

In triangle PQR, q = 8 cm, r = 6 cm and cos P = \(\frac{1}{12}\). Calculate the value of p.

  • A. \(\sqrt{108}\) cm
  • B. 9 cm
  • C. \(\sqrt{92}\) cm
  • D. 10 cm
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Correct Answer: Option C
Explanation

Using the cosine rule, we have

\(p^{2} = q^{2} + r^{2} - 2qr \cos P\)

\(p^{2} = 8^{2} + 6^{2} - 2(8)(6)(\frac{1}{12})\)

= \(64 + 36 - 8\)

\(p^{2} = 92 \therefore p = \sqrt{92} cm\)

There is an explanation video available below.


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Explanation Video

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free