Find the length of a chord which subtends an angle of 90° at the centre of a circle whose radius is 8 cm.
Length of chord = \(2r \sin (\frac{\theta}{2})\)
= \(2 \times 8 \times \sin (\frac{90}{2})\)
= \(16 \times \frac{\sqrt{2}}{2}\)
= \(8\sqrt{2} cm\)
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}