What is the derivative of t2 sin (3t - 5) with respect to t?
a
6t cos (3t - 5)
b
2t sin (3t - 5) - 3t2 cos (3t - 5)
c
2t sin (3t - 5) + 3t2 cos (3t - 5)
d
2t sin (3t - 5) + t2 cos 3t
Explanation
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Ifechuks1
13 years ago
t^2sin(3t-5)
=> let u=t^2,,,v=sin(3t-5).
du/dx=2t...
V=sin(3t-5)let u=3t-5... V=sin u. dv/du=cos u. But u=3t-5. du/dx=3.
dv/dx=du/dx X dv/du.=>3cos(3t-5)...
UV= V X du/dx + U X dv/dx.
=>sin(3t-5) X 2t. + t^2 X 3cos(3t-5).
=>2tsin(3t-5)+3t^2cos(3t-5).= C is the ans.
