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1991 WAEC Mathematics Theory From a horizontal distance of 8.5 km, a pilot observes that the angles of depression...

Mathematics
WAEC 1991

From a horizontal distance of 8.5 km, a pilot observes that the angles of depression of the top and the base of a control tower are 30° and 33° respectively. Calculate, correct to three significant figures :

(a) the shortest distance between the pilot and the base of the control tower;

(b) the height of the control tower.

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Explanation

Let T and B be the top and base of the control tower respectively; P, the point of pilot's observation and PS, the line of observation.

(a) Shortest distance is |PB|.

\(\therefore \cos 33° = \frac{8.5}{PB}\)

\(PB = \frac{8.5}{\cos 33} = \frac{8.5}{0.8387}\)

\(|PB| = 10.135km \approxeq 10.1km\)

(b) Height of the control tower = |SB| - |ST|

\(\therefore \tan 33° = \frac{|SB|}{8.5 km} \implies |SB| = 8.5 \tan 33°\)

\(|SB| = 5.52 km\)

\(\tan 30° = \frac{|ST|}{8.5 km} \implies |ST| = 8.5 \tan 30°\)

\(|ST| = 4.907 km\)

\(\therefore\) The height of the tower = 5.52 km - 4.907 km = 0.613 km.


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