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1991 WAEC Mathematics Theory A man bought 5 reams of duplicating paper, each of which are supposed to contain...

Mathematics
WAEC 1991

A man bought 5 reams of duplicating paper, each of which are supposed to contain 480 sheets. The actual number of sheets in the packets were : 435, 420, 405, 415 and 440. 

(a) Calculate, correct to the nearest whole number, the percentage error for the packets of paper;

(b) If the agreed price for a full ream was N35.00, find, correct to the nearest naira, the amount by which the buyer was cheated.

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Explanation

(a) Sheets expected from 5 packets = \(480 \times 5 = 2400\)

Actual sheet contained in the packets = \(435 + 420 + 405 + 415 + 440 = 2115\)

Error in supply = 2400 - 2115 = 285 sheets.

\(\therefore\) Percentage error = \(\frac{285}{2400} \times 100% = 11.875%\)

\(\approxeq 12%\)

(b) If 1 packet = 480 sheets cost N35.00

\(\therefore \text{2400 sheets cost } \frac{2400}{480} \times N35.00 = N175.00\)

Amount of buyer was cheated = \(\frac{Error \times N175}{\text{Expected no of sheets}}\)

\(\frac{N285 \times 175}{2400} = N20.78\)

The buyer was cheated by N21 to the nearest naira.


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